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2x^2=75^2
We move all terms to the left:
2x^2-(75^2)=0
We add all the numbers together, and all the variables
2x^2-5625=0
a = 2; b = 0; c = -5625;
Δ = b2-4ac
Δ = 02-4·2·(-5625)
Δ = 45000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{45000}=\sqrt{22500*2}=\sqrt{22500}*\sqrt{2}=150\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-150\sqrt{2}}{2*2}=\frac{0-150\sqrt{2}}{4} =-\frac{150\sqrt{2}}{4} =-\frac{75\sqrt{2}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+150\sqrt{2}}{2*2}=\frac{0+150\sqrt{2}}{4} =\frac{150\sqrt{2}}{4} =\frac{75\sqrt{2}}{2} $
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